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\begin{equation*} \DeclareMathOperator\Coim{Coim} \DeclareMathOperator\Coker{Coker} \DeclareMathOperator\Ext{Ext} \DeclareMathOperator\Hom{Hom} \DeclareMathOperator\Im{Im} \DeclareMathOperator\Ker{Ker} \DeclareMathOperator\Mor{Mor} \DeclareMathOperator\Ob{Ob} \DeclareMathOperator\Sh{Sh} \DeclareMathOperator\SheafExt{\mathcal{E}\mathit{xt}} \DeclareMathOperator\SheafHom{\mathcal{H}\mathit{om}} \DeclareMathOperator\Spec{Spec} \newcommand\colim{\mathop{\mathrm{colim}}\nolimits} \newcommand\lim{\mathop{\mathrm{lim}}\nolimits} \newcommand\Qcoh{\mathit{Qcoh}} \newcommand\Sch{\mathit{Sch}} \newcommand\QCohstack{\mathcal{QC}\!\mathit{oh}} \newcommand\Cohstack{\mathcal{C}\!\mathit{oh}} \newcommand\Spacesstack{\mathcal{S}\!\mathit{paces}} \newcommand\Quotfunctor{\mathrm{Quot}} \newcommand\Hilbfunctor{\mathrm{Hilb}} \newcommand\Curvesstack{\mathcal{C}\!\mathit{urves}} \newcommand\Polarizedstack{\mathcal{P}\!\mathit{olarized}} \newcommand\Complexesstack{\mathcal{C}\!\mathit{omplexes}} \newcommand\Pic{\mathop{\mathrm{Pic}}\nolimits} \newcommand\Picardstack{\mathcal{P}\!\mathit{ic}} \newcommand\Picardfunctor{\mathrm{Pic}} \newcommand\Deformationcategory{\mathcal{D}\!\mathit{ef}} \end{equation*}

On I. Vanni left comment #11705 on Section 65.12 in Algebraic Spaces

Typo after Definition 02YY: "Note that if T is a schemes".


On David Grimm left comment #11704 on Lemma 54.15.3 in Resolution of Surfaces

The hypothesis "in the situation above" has unfortunately quite a few possible interpretations. To author it is probably quite logical which ones are meant. Does it mean for example that one already assumes the possibility to resolve singularities of Y (absolutely) as a prerequisite to have embedded resolution ? I think with a more precisely stated hypothesis, this Lemma could become more usefull as a source for reliable citation.


On David Grimm left comment #11703 on Lemma 54.15.3 in Resolution of Surfaces

The hypothesis "in the situation above" has unfortunately quite a few possible interpretations. To author it is probably quite logical which ones are meant. Does it mean for example that one already assumes the possibility to resolve singularities of Y (absolutely) as a prerequisite to have embedded resolution ? I think with a more precisely stated hypothesis, this Lemma could become more usefull as a source for reliable citation.


On Nick left comment #11702 on Equation 107.5.21.1 in The Geometry of Algebraic Stacks

Equation (5.21.1) does not have proper line breaks in the PDF file because the {equation} environment does not support line breaks. Please use the {align} environment instead.


On thesnakefromthelemma left comment #11701 on Lemma 4.19.5 in Categories

The issue mentioned by the above commenter is a good example of the too simple to be simple phenomenon; a cute way to correct the statement is to modify the hypothesis to that for any finite (possibly empty!) family of objects of , there exists an object and family of morphisms . (But, alas, it is perhaps more idiomatic to just stipulate additionally that is nonempty. What can one do?)

It's also worth noting that (IINM) this claim holds not just in but more generally in the category of models of any algebraic theory (in the sense of universal algebra)!


On Alex Scheffelin left comment #11700 on Proposition 41.19.4 in Étale Morphisms of Schemes

It should day , currently the 2 is missing.


On David Holmes left comment #11699 on Section 110.16 in Examples

Trivial off by 1 error: in (1), should be "of dimension ". For example, if then and localising there gives a DVR. This does not affect anything anywhere, of course.

Disclosure: this was pointed out to me by an LLM when I was having it do a some surveying for https://adjectivesproject.org. Not sure how you feel about LLM-inspired contributions...


On left comment #11698 on Section 10.107 in Commutative Algebra

For the record, a characterization on ring epimorphisms is given in Corollary 4. I definitely could not find this in the existing literature on ring epis.


On left comment #11697 on Section 26.23 in Schemes

This result could fit to this section (although I don't know if it serves any purpose):

Monomorphisms are local on source and target in the following sence: Let be a morphism of schemes and let and be open covers such that . Then is monic if and only if is a monomorphism for every .

The proof is not difficult.


On left comment #11696 on Lemma 26.23.7 in Schemes

Hypothesis (2) may be relaxed to

(2') for any the ring map is a ring epimorphism.

Moreover, it turns out monicity is equivalent to (1)+(2'), even in the category of ringed spaces, see here.


On Sanjana chauhan left comment #11695 on Definition 46.3.1 in Adequate Modules


On left comment #11694 on Section 65.12 in Algebraic Spaces

Regarding “it is clear that the collection of open subspaces of is a set (as is a site, hence a set).” The argument is foundations-dependent, but the fact the collection of open subspaces of is a set is a foundations-independent fact by Properties of Spaces, Lemma 66.4.8. Maybe this other route is worth mentioning?


On left comment #11693 on Section 66.4 in Properties of Algebraic Spaces

Inside Definition 66.4.1 it is asserted the non-obvious fact that the collection of points of an algebraic space is a set. Shouldn't one justify this by invoking Lemmas 66.4.2 and 66.4.5?


On left comment #11692 on Lemma 100.4.1 in Properties of Algebraic Stacks

In the proof, after “choose any field and embeddings and agreeing on ” one could add “see Fields, Lemma 9.6.9.”


On left comment #11691 on Section 66.4 in Properties of Algebraic Spaces

Right before Definition 66.4.1, one could replace “we omit the verification that this defines an equivalence relation” by “from Fields, Lemma 9.6.9, we see this defines an equivalence relation.”


On left comment #11690 on Section 26.13 in Schemes

Right before Lemma 26.13.3, after “this defines an equivalence relation, because given any set of field extensions there exists some field extension such that all the field extensions are contained in the extension ,” one could say “see Fields, Lemma 9.6.9, for the case when there are finitely many .”


On left comment #11689 on Lemma 9.6.9 in Fields

do we really need flatness? One could say that is non-zero because it is a -vector space of dimension .


On anonymous left comment #11688 on Section 66.24 in Properties of Algebraic Spaces

11687 infact you can do better. You can find a Noetherian affine scheme surjecting onto the algebraic space.


On left comment #11687 on Section 66.24 in Properties of Algebraic Spaces

Maybe it is worth to remark that an algebraic space being quasi-compact and locally Noetherian is equivalent to existence of an étale surjection from a Noetherian scheme .

It is clear that the condition is sufficient. Conversely, suppose is quasi-compact and locally noetherian. Let be étale surjections from a quasi-compact scheme and a locally noetherian scheme . Then is an étale surjection of schemes. Thus is locally Noetherian. Since is also an étale surjection, is locally noetherian, i.e., is Noetherian.


On K. F. left comment #11685 on Lemma 10.141.2 in Commutative Algebra

In the proof of Lemma 02HT, the displayed equation seems to contain a typo. The index should be , not , since is free with basis .